On Aug. 7, 2009, David Ronis wrote:
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I've got a trivial integral that maxima doesn't seem to be able to do;
I'm having trouble believing this. Can someone confirm?
integrate(%e^(-kappa*r)*sin(k*r),r,0,inf);
(kappa>0) I get the integral form when I do this.
(The answer is k/(k^2+kappa^2))
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Hi David,
Using 5.18.1 on Windows XP
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(%i1) display2d:false$
(%i2) assume(k>0,kp>0)$
(%i3) integrate (exp(-kp*r)*sin(k*r),r,0,inf );
(%o3) k/(kp^2+k^2)
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Best Wishes,
Ted Woollett