Newbie Question: Are arguments in a function definition bound when function is called?
Subject: Newbie Question: Are arguments in a function definition bound when function is called?
From: Robert Dodier
Date: Wed, 26 Aug 2009 10:21:57 -0600
On Wed, Aug 26, 2009 at 9:21 AM, Stavros Macrakis<macrakis at alum.mit.edu> wrote:
> It binds the dummy variable, but in the expression f(3), f is a reference to
> the *function value* of f if there is one, and only if it is not is it the
> value binding.
>
> Does that make it any clearer?
Well, this is just a rephrasing of what the existing code does, right?
There aren't any fundamental principals in play here.
Just trying to make it clear to the original poster that the
present, confused state of affairs is more a bug than a feature.
Robert Dodier