access results of linsolve



On Tue, 2009-12-15 at 18:43 -0600, Barton Willis wrote:
> (%i1) ssol[1] : 42$
> 
>  (%i2) ssol : linsolve([C1*3-2,C2*1+4],[C1,C2]);
>  (%o2) [C1=2/3,C2=-4]
> 
> ssol[1] --> 42, not C1=2/3
> 
>  (%i3) ssol[1];
>  (%o3) 42
> 
> But inpart(ssol,1) is OK
> 
>  (%i4) inpart(ssol,1); 

Another way to access the list ssol, instead of the hashed array ssol,
which I find more intuitive is:

(%i5) first(ssol);
(%o5) C1 = 2/3
(%i6) second(ssol);
(%o6) C2 = -4

I think that using the same notation a[i] for lists and hashed arrays is
very confusing and we should change it.
Regards,
Jaime