On 2010-01-25 18:49 +0000, Leo Butler wrote:
> Solve eq2 for f=f(h,Nw).
> Since eq1 is linear in h and independent of f, solve eq1 for h=h(Nw).
> Substitute h,f into eq3, to get a solution for Nw in terms of the
> parameters. Back substitute to get f and h. Finally, check your answer
> for f with that for eq4.
>
> Unfortunately, the expressions grow rapidly in size. I would suggest rethinking
> why you've put so many parameters into these equations. For example,
> I think you can 'remove' 3 or 4 parameters from eq1 by rewriting it like
>
> a - Nw*(1-h) + NQ*h - Nw*b = 0
>
> Finally, since your system is quadratic in f,h,Nw, maybe it would make
> sense to solve the linearised system.
Thanks for this hint. Actually if I add the first three eqs, Nw can be
expressed in f and so the equation be reduced to two. Since I also need
to integrate f along another axis, I think I will go straight to
numerical computation.
> I should have said earlier: Welcome to Maxima.
Thanks again. You have been very helpful.
Leo