limit(signum(a*x+b),x,1/a) = 'limit(signum(a*x+b+1),x,0) is OK, but
limit(signum(a*x+b),x,1/a) = signum(b+1) is wrong. To see this
let a = 1 and b = -1, then then limit(signum(x-1),x,1) = und # signum(-1
+1).
Barton
-----maxima-bounces at math.utexas.edu wrote: -----
>(%i13)?limit(signum(a*x+b),x,1/a);
>(out13)?'limit(signum(a*x+b+1),x,0)
>
>The?plus?one?is?okay?but?a*x?should?not?be?in?there.??I?think?the?answer
>should?be?'limit(signum(b+1),x,0)?or?just
>signum(b+1).