kdelta evaluation in ctensor?




Viktor T. Toth <vttoth <at> vttoth.com> writes:

> 
> You can actually get the desired result by inserting this before eq(Beqn):
> 
> for i thru 3 do for j thru 3 do for k thru 3 do for l thru 3 do for m thru 3
> do for n thru 3 do kdelta[i,j,k,l,m,n]:kdelta([i,j,k],[l,m,n]);
> 
> Not very elegant, I know. ic_convert() is long overdue for an overhaul, as
> it doesn't play very nicely with a number of things, including
> kdelta/levi_civita.
> 
> Viktor

Hi Viktor, 

that was really fast! 
and the solution is good enough for my purposes.
thanks a lot. 

-karl