Hi,
I am using maxima for few days. So, please excuse me if I ask
something very primitive.
I tried to execute the following command to solve the recurrence relation p(x).
(%i7) grind(solve_rec(p(x)=2+p(x-1)+p(x-2),p(x),p(0)=0));
I got the following answer:
p(x) = (sqrt(5)-1)^x*(2-%k[2])*(-1)^x/2^x+(sqrt(5)+1)^x*%k[2]/2^x-2$
I know the RR is of order 2 so need at least 2 base cases. However, I
give one base case and wanted to see how it behaves.
My question is what is the meaning of %k[2] in the above result.
Many thanks in advance.
--Masud