Decomposition of x^4+x^3+x^2+x+1 (Yu Hsiung Huang)
Subject: Decomposition of x^4+x^3+x^2+x+1 (Yu Hsiung Huang)
From: 黃 裕雄
Date: Sat, 15 May 2010 21:56:20 +0800
> From: maxima-request at math.utexas.edu
> Subject: Maxima Digest, Vol 46, Issue 29
> To: maxima at math.utexas.edu
> Date: Sat, 15 May 2010 08:34:39 -0500
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> Today's Topics:
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> 1. Re: Decomposition of rationnal fractions (Michel Talon)
> 2. check if a number is rational (Christian Stengg)
> 3. Re: check if a number is rational (Barton Willis)
> 4. Re: Question concerning sum (Dieter Kaiser)
> 5. Describe issue? (Raymond Toy)
> 6. Navier-Stokes equations and itensor package. (Grigory Sarnitskiy)
> 7. Re: Describe issue? (Dieter Kaiser)
> 8. Q in solve Chinese Remainder Theroem or inequality equation (? ??)
> 9. Q in wxMaxima0.8.2 in ubuntu9.10 (? ??)
>
>
> ----------------------------------------------------------------------
>
> Message: 1
> Date: Fri, 14 May 2010 09:31:52 +0200
> From: Michel Talon <talon at lpthe.jussieu.fr>
> To: maxima at math.utexas.edu
> Subject: Re: [Maxima] Decomposition of rationnal fractions
> Message-ID: <hsiu98$pgb$1 at dough.gmane.org>
> Content-Type: text/plain; charset=iso-8859-15
>
> Nicolas FRANCOIS wrote:
>
> > Le Thu, 13 May 2010 23:05:12 +0100,
> > Jaime Villate <villate at fe.up.pt> a ?crit :
> >
> >> On Thu, 2010-05-13 at 23:00 +0100, Jaime Villate wrote:
> >> > (to obtain its formal series equivalent \sum a_nX^n, a_n being the
> >> > > number of ways to pay n? using 1, 2 and 5? corners (no, there
> >> > > is no such thing as a 5? corner, but there's a 5? banknote !)).
> >> Oops, sorry; I did not read this part before my previous reply to your
> >> message. Then the partial fractions expansion that I told you is not
> >> what you need.
> >
> > Yes it is, and I'm aware of the partfrac function. My problem is it
> > does only work in Q[X] : I would like to force the use of complex
> > roots, to decompose 1+x+x^2+x^3+x^4 into a product of factors X-w,
> > where w is one of the fifth roots of 1 distinct from 1.
> >
> > So my question is : is there a way to work in an extension of Q(X) ?
> >
> > \bye
> >
>
> You can work in an extension by first using "factor" in an extension.
> For example:
>
> (%i6) factor(x^4+1,w^2+1);
> 2 2
> (%o6) (x - w) (x + w)
>
> So all you need is first adjoint the appropriate roots.
>
>
> --
>
> Michel Talon
>
I don' t know to decomposition of x^4+x^3+x^2+x+1 in maxima
but we know
x^5-1=0
(x-1)(x^4+x^3+x^2+x+1)=0
divide(x^5-1,x-1);
(%o1) [x^4+x^3+x^2+x+1,0]
so, we can
solve(x^5-1);
(%o1) [x=%e^((2*%i*%pi)/5),x=%e^((4*%i*%pi)/5),x=%e^(-(4*%i*%pi)/5),x=%e^(-(2*%i*%pi)/5),x=1]
the answer is the factors of x^4+x^3+x^2+x+1
Yu Hsiung Huang
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