Subject: Solving an equation with trigonometrics...
From: Leo Butler
Date: Tue, 6 Jul 2010 16:53:01 +0100 (BST)
On Tue, 6 Jul 2010, Julien Martin wrote:
< Hello,
<
< I need to solve the following equation in order to find the value of "y" using Maxima:
<
< x=-1/2*arctan(y/2)+3*%pi/8;
<
< I would like to get a value of "y" instead of this:
< [arctan(y/2)=(3*%pi-8*x)/4]
<
< Can anyone help please?
<
Maxima does not know the 'arctan' fn, it uses 'atan'.
Leo
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