Trigonometric definite integral resulting insinc-likefunction
Subject: Trigonometric definite integral resulting insinc-likefunction
From: Richard Hennessy
Date: Sat, 17 Jul 2010 22:41:45 -0400
"Other than a conditional expression (or an asksign), what is the workaround?"
There is none that I know of but I don't like asksign.
From: Stavros Macrakis
Sent: Saturday, July 17, 2010 7:08 PM
To: Barton Willis
Cc: Maxima mailing list ; Robert Dodier
Subject: Re: [Maxima] Trigonometric definite integral resulting insinc-likefunction
If the singularity isn't removable, then of course you need some other approach....
On Sat, Jul 17, 2010 at 17:32, Barton Willis <willisb at unk.edu> wrote:
-----macrakis at gmail.com wrote: -----
>Rather than say that the result of integrate(cos(a*x),x) should be (if a=0
>then x else sin(a*x)/a), I would prefer to say that the Maxima expression
>sin(a*x)/a denotes the function defined by that expression when a<>0 and
>its analytical continuation when a=0.
>The problem with that of course is that 'subst' doesn't work that way.
>There are two solutions to that: 1) to keep subst as it is, and say that
>it has a strictly syntactic interpretation of expressions (which is true);
>2) to make subst essentially a synonym for limit.
That works for many functions, but how about:
(%i96) load(abs_integrate)$
(%i99) subst(x=3/2, integrate(floor(m*x),x))$
(%i100) [limit(%,m,0,'minus), limit(%,m,0,'plus)];
(%o100) [-3/2,0]
The expression %o99 has a nonremovable singularity at 0. Other than a
conditional expression (or an asksign), what is the workaround?
--Barton
--------------------------------------------------------------------------------
_______________________________________________
Maxima mailing list
Maxima at math.utexas.edu
http://www.math.utexas.edu/mailman/listinfo/maxima