Hello Raymond,
I want to do the following:
Expand
(1-%theta/%mu)^-1
as a Binomial series knowing %mu is a constant.
Here is what I tried in Maxima:
(1-%theta/%mu)^-1;
taylor(%,%theta,0,10);
You see, I don't understand about which point to expand given what I want to
do. What do you suggest I replace the third argument (i.e. 0) with?
Julien.
2010/7/26 Raymond Toy <toy.raymond at gmail.com>
> On 7/26/10 10:18 AM, Julien Martin wrote:
> > If from a mathematical point of view, the binomial series yields the
> > same result as the taylor expansion around zero, then taylor suits me
> > fine. Can someone please confirm this is the one and same thing?
> Well, to me binomial series is (1+x)^n, expanded out. A general Taylor
> expansion about zero is much more than that, so maybe the answer is no,
> they're not the same.
>
> But certainly a taylor expansion of (1+x)^n would give the binomial
> series, since power series are unique and both the taylor series and the
> binomial series converge to the same function over a suitable domain.
>
> Ray
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