Stavros Macrakis wrote:
> Why do you have radcan in there? Radcan does not guarantee any
> particular root. Why not just rootscontract(sqrt(...)/sqrt(...))?
Thank you once again. I am beginner. The manual says only that
"radscan(expr) simplifies expr" and hence I didn't expect that
the result could under circumstances involve a change of sign.
Would it be favourable that the manual gives a warning about this?
M. K. Shen