Find the angle between two tangents by iterating en2



On 9/3/10, William Porter <wmporter.omegapar at comcast.net> wrote:

> en2: 15 gives me ang: 0.6435011088
>
> en2: 25 gives me ang: 0.3947911197
>
> etc. en2.
>
>  en2: 55 gives me ang: 0.1813197744

Well, probably the easiest thing is the built-in function find_root.
Something like

  find_root (<some expression>, en2, 10, 80);

best,

Robert Dodier