On 9/29/10 3:58 AM, Eli Brosh wrote: > (%i53) f1:(x/x0)^a; > (%o53) (x/x0)^a > (%i48) f2:(x/x0)^(a-1); > (%o48) (x/x0)^(a-1) > > Now, f3 is the division: > (%i52) f3:f1/f2; What version of maxima are you using? With the recent CVS version, f3 is x/x0. Anyway, maybe ratsimp(f3) will produce what you want. Ray