simplifying powers



This doesn't work because Vo is not the same thing as V0.  When you replace
Vo with V0, f2/f3 is beta*ge*T^2/(2*V0).

             -s

PS It would be better if you could send self-contained, reproducible code.
 In the example below, %i112 doesn't evaluate to %o112 because Fe is not
defined.

On Wed, Sep 29, 2010 at 13:44, Eli Brosh <ebrosh1 at gmail.com> wrote:

> I am using wxmaxima 0.8.4 with maxima 5.20.1
> I checked it. The example I sent really does work. But a slightly different
> example does not:
>
>
> (%i111) f1:-1/2*beta*(V/V0)^ge*T^2;
> (%o111) -(beta*T^2*(V/V0)^ge)/2
> (%i112) f2:diff(-Fe,V);
> (%o112) (beta*ge*T^2*(V/V0)^ge)/(2*V)
> (%i113) f3:(V/Vo)^(ge-1);
> (%o113) (V/Vo)^(ge-1)
> (%i114) f4:f2/f3;
> (%o114) (beta*ge*T^2*(V/Vo)^(1-ge)*(V/V0)^ge)/(2*V)
>
> Why doesn't it simplify ?
> I tried ratsim, trigsimp and some others.
>
> Thanks
> Eli
>
>
>
>
>
> On Wed, Sep 29, 2010 at 6:13 PM, Stavros Macrakis <macrakis at alum.mit.edu>wrote:
>
>> What version of Maxima are you using?  This works correctly in 5.20.1:
>>
>> (%i1) f1:(x/x0)^a;
>> (%o1) (x/x0)^a
>> (%i2) f2:(x/x0)^(a-1);
>> (%o2) (x/x0)^(a-1)
>> (%i3) f3:f1/f2;
>> (%o3) x/x0
>>
>> For more complicated simplifications which Maxima does not perform
>> automatically, there is a large number of functions to try for reorganizing
>> expressions.  Some that are worth trying are ratsimp, factor, factorsum,
>> expand, multthru.  To get more information on these, type, e.g.
>>
>> (%i4) ? ratsimp
>>  -- Function: ratsimp (<expr>)
>>  -- Function: ratsimp (<expr>, <x_1>, ..., <x_n>)
>>      Simplifies the expression <expr> and all of its subexpressions,
>>      including the arguments to non-rational functions.  The result is
>> ...
>>
>> On Wed, Sep 29, 2010 at 03:58, Eli Brosh <ebrosh1 at gmail.com> wrote:
>>
>>> Hello,
>>> I hope people on the maxima mailing list can help me with the following.
>>>
>>> I defined the functions f1 and f2 as:
>>> (%i53) f1:(x/x0)^a;
>>> (%o53) (x/x0)^a
>>> (%i48) f2:(x/x0)^(a-1);
>>> (%o48) (x/x0)^(a-1)
>>>
>>> Now, f3 is the division:
>>> (%i52) f3:f1/f2;
>>> (%o52) x^a*(x/x0)^(1-a)
>>>
>>> How can I force maxima to simplify f3 down to (x/x0) ?
>>> Now this is a simple example. What can I do with more complex expressions
>>> where I do not have a good idea about the end result?
>>>
>>> Thanks,
>>> Eli
>>>
>>>
>>> _______________________________________________
>>> Maxima mailing list
>>> Maxima at math.utexas.edu
>>> http://www.math.utexas.edu/mailman/listinfo/maxima
>>>
>>>
>>
>