"radcan itself never produces abs().
You (and others) seem to think that sqrt( (x^2-2*x+1)/x) is equal to
sqrt(1/x)*abs(x-1).
It is not."
I said
"Semantics. If you intend to integrate the result then you should simplify
with something other than radcan."
You said
"You (and others) seem to think that sqrt( (x^2-2*x+1)/x) is equal to
sqrt(1/x)*abs(x-1).
It is not."
I didn't say they were equal. I would say that I choose a different
interpretation which allows me to say that they are equal. You are wrong
when you say "It is not [equal]." In my interpretation it is equal, in your
interpretation it is not equal and your interpretation is not better than
mine.
Rich
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