> I guess, under the interpretation that sqrt(x^2) = x then this answer is
> right.
>
I don't like the interpretation sqrt(x^2) = x, I just thought Maxima is
using it to do the integral, which is why I though it was wrong in the first
few emails on this subject.
"Well, if sqrt(x^2)=x, then how do you feel about
sqrt( (1-y)^2) = 1-y ?
and
sqrt((y-1)^2) = y-1 ?
Of course, (1-y)^2 = (y-1)^2, so the sqrt() could be either of
those two things, or a third, which is abs(1-y) which chooses half of
one answer and half of the other.
RJf"
I like the interpretation sqrt(x^2) = abs(x) better so I like sqrt((1-y)^2)
= abs(1-y). Maxima makes up the rule to use based on each input line and it
is _not_ consistent.
Rich