inverse expression

• Subject: inverse expression
• From: Sebastian P. Luque
• Date: Thu, 18 Nov 2010 12:47:18 -0600

On Thu, 18 Nov 2010 13:43:51 -0500,
Stavros Macrakis <macrakis at alum.mit.edu> wrote:

> (%i65) ex: A * exp(-b * exp(-k * x)) = y $
> (%i66) solve(ex,x);
> (%o66) [x = log(b/log(A/y))/k]

Neat, so the expression needs to be an actual equation, not a function.
Thanks!

-- 
Seb

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