Maybe this is what you would like:
(%i1) l = A * exp(-b * exp(-k * x));
(%o1) l=%e^(-b*%e^(-k*x))*A
(%i2) solve(%,x);
(%o2) [x=log(b/log(A/l))/k]
--Barton
-----maxima-bounces at math.utexas.edu wrote: -----
Hi,
Given the following definition for a growth model, say length as a
function of age (x):
eq(x):=A * exp(-b * exp(-k * x))
How can one obtain the expression for x as a function of length in
Maxima? ?Based on my very limited experience with Maxima, this seems to
be a job for solve(), but I'm not sure if this requires a different
expression to start with. ?Thanks in advance for any pointers.
Cheers,
--
Seb
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