exp(complex)^k

• Subject: exp(complex)^k
• From: Stavros Macrakis
• Date: Thu, 20 Jan 2011 13:11:04 -0500

declare(z,complex)$
(%e^x)^y => %e^(x*y)
(%e^z)^y => (%e^z)^y

Can I turn off "pedantic mode" so that the second yields %e^(z*y)?

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