Hello,
I'm new to this mailing list and therefore I do not know, weather this
is the right place for asking quastions.
My question is, is there a way to substitute differential operators in
explorations.
Maybe an example can show what I mean.
There are two different things I want to do. the first one is to
substitute only the function, not the derivatives, to zero.
Mathematically:
f(x=a) = 0 where a can be a constant number for example 0.
therefore I want to do (only the inputs):
Input: depends( f , x );
Input: P : x - f / diff( f , x );
Input: atvalue( f( x ) , x = 0 , 0); # or something else.
output for P
x - f / (d/dx f);
Expected output for P after substitution or whatever:
P = x # because of the f(0) = 0
What I have tried:
1)
Input: P,x=0;
Output:
Attempt to differentiate with respect to a number: 0
2)
Input: subst(0, f, P);
Output: Division by 0
Is there any other way to simplify those equations?
The second thing is about substitutions aswell but here I want to
substitute a whole expr like : "(d^2/dx^2) t" to A(x) or whatever.
Is there a way to do it?
Example:
Input: Q : P + diff( t , x);
Output: x - f / (d/dx f) + d/dx t;
after that something like:
Input: subst( Q , diff( t ,x) , a)
Expected Output: x - f / (d/dx f) + a;
It would be great, if you would have an answer for me.
Tanks.