This method requires insight:
?(%i20) factor(integrate((3*t+2)^5,t,-2/3,x));
?(%o20) (3*x+2)^6/18
Sometime ago there were, I think, other suggestions for doing this on the list.
I looked, but I wasn't able to find them...
--Barton
-----maxima-bounces at math.utexas.edu wrote: -----
>Hi?there!
>
>when?I?integrate?the?expression?"(3*x+2)^5",?maxima?returns?the?fully?
>expanded?polynom?"(81*x^6)/2+162*x^5+270*x^4+240*x^3+120*x^2+32*x".?
>Albeit?correct,?I'd?like?to?massage?this?into?the?form?"?1/18(3x+2)^6".?
>Is?there?any?way?to?do?this?