M. M. <maclair at gamma.ttk.pte.hu> writes:
> Is there a way to get the correct answer from Maxima to
> "integrate(1/x,x,0,1)"?
> (I mean infinity.)
You could ask for the limit of the integral as the lower bound
approaches zero from the right:
(%i2) assume(e>0, e<1);
(%o2) [e > 0,e < 1]
(%i3) limit(integrate(1/x,x,e,1),e,0,plus);
(%o3) inf
Mark