'sum' doesn't evaluate infinite sums numerically.
Simpsum tries to find a closed-form *symbolic* solution.
On 2011-04-05, Chi Ben <xbenchi at gmail.com> wrote:
> Hi All,
>
> I was using this sum function:
>
>> *sum((tan(1/(2*x))-tan(1/(2*x+1))),x,1,inf),simpsum=true;*
>>
>
> However, the evaluated result is the mathematical expression instead of a
> float value, even with simpsum=true.
> How do I get a value?
>
> Sincerely,
>
> Chi Ben
>
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