"Thomas D. Dean" <tomdean at speakeasy.org> writes:
> Now, the part I do not understand:
>
> (%i8) subst(sk, xx);
> subst: improper argument: sk
> -- an error. To debug this try: debugmode(true);
>
> I do not understand how the subst(sk,...) expression works in the
> context of makelist and expand.
>
> Can someone explain this?
makelist is a macro and you read it as follows.
makelist(expand(subst(sk, xx)),sk, args(sol));
means:
(1) For each element of args(sol) (which is a list), bind a dummy
variable called sk to its value
(2) Now call the code "expand(subst(sk, xx))" with this name binding in
place.
So you should find that
expand(subst(args(sol)[1], xx))
works and gives you the first element of the list you got with Barton's
code.
Rupert
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