The number is simply too big to be factored by Maxima's algorithm. You
might like to try other software with better support for computational
number theory, such as Pari/GP. I suspect that the numbers in question
(from here <http://www.immortaltheory.com/NumberTheory/RuthAaron.htm>;) were
produced by a polynomial, so all you need to do is to solve the appropriate
polynomial f(x)=n, where n is the smaller of the two numbers.
-Alasdair
On Wed, Sep 14, 2011 at 7:25 AM, Matematicas <metodosu at gmail.com> wrote:
> Numbers are called Ruth-Aaron pair, such as {714, 715}. Are consecutive
> numbers {n, n +1} such that the sum of the prime factors of each are
> equal.
>
> Let's see
>
> 714 = 2x3x7x17
> 715 = 5x11x13
>
> Sum of divisors of 714 = 29 = Sum of divisors of 715
>
>
>
> FACTORS FOR EACH OF THE FOLLOWING TWO NUMBERS. COULD NOT DERIVE
>
> A number of 135 digits es1 Aoron
>
> *
> 296603151077074197308684124715622560525294501766069587161483751777320391554230009758029564174782423278870115094641644418265512090475910
> *
>
>
> The following of the former is
>
> *
> 296603151077074197308684124715622560525294501766069587161483751777320391554230009758029564174782423278870115094641644418265512090475911
> *
>
> The problem is that the command ifactor(n) don't work, generate an error,
> can help me??
>
> 1 <#13264ae44588bf30_sdfootnote1anc>
> http://www.immortaltheory.com/NumberTheory/RuthAaron.htm
>
>
>
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>
>
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