Maxima :o)
No magick here. Actually, I read the page given by "Matematicas". There is
an interesting relation :
*M = (1800p3 - 1310p2 - 50p - 1) (1800p3 - 1220p2 - 130p - 1)
M-1 = 2 * 5 * p * (90p2 - 61p - 6) (3600p3 - 2620p2 - 120p - 3)*
With this the problem is quite easy. This gives (almost) p :
inrt(floor(n/1800^2), 6);
But you may find p by "direct" factorization, since it's quite small.
2011/9/14 Alasdair McAndrew <amca01 at gmail.com>
> Nice - what software did you use for the factorization?
>
> -Alasdair
>
>
> 2011/9/14 Biche de C?rynie <bichedecerynie at gmail.com>
>
>> Prime factors for your numbers :
>>
>> 2
>> 5
>> 2122943609450249057621
>> 405620061201508643988375124643817406843652803
>> 34444340671702467488860342883734479061576134487870291451728421045657
>>
>> And
>>
>> 17222170335851233744430171441867239530788067265164581820366701099039
>> 17222170335851233744430577061928441039432055599953297058218812657049
>>
>> Jean-Claude Arbaut
>>
>>
>>
>> On Wed, Sep 14, 2011 at 2:21 AM, Alasdair McAndrew <amca01 at gmail.com>wrote:
>>
>>> The number is simply too big to be factored by Maxima's algorithm. You
>>> might like to try other software with better support for computational
>>> number theory, such as Pari/GP. I suspect that the numbers in question
>>> (from here <http://www.immortaltheory.com/NumberTheory/RuthAaron.htm>;)
>>> were produced by a polynomial, so all you need to do is to solve the
>>> appropriate polynomial f(x)=n, where n is the smaller of the two numbers.
>>>
>>> -Alasdair
>>>
>>> On Wed, Sep 14, 2011 at 7:25 AM, Matematicas <metodosu at gmail.com> wrote:
>>>
>>>> Numbers are called Ruth-Aaron pair, such as {714, 715}. Are consecutive
>>>> numbers {n, n +1} such that the sum of the prime factors of each are
>>>> equal.
>>>>
>>>> Let's see
>>>>
>>>> 714 = 2x3x7x17
>>>> 715 = 5x11x13
>>>>
>>>> Sum of divisors of 714 = 29 = Sum of divisors of 715
>>>>
>>>>
>>>>
>>>> FACTORS FOR EACH OF THE FOLLOWING TWO NUMBERS. COULD NOT DERIVE
>>>>
>>>> A number of 135 digits es1 Aoron
>>>>
>>>> *
>>>> 296603151077074197308684124715622560525294501766069587161483751777320391554230009758029564174782423278870115094641644418265512090475910
>>>> *
>>>>
>>>>
>>>> The following of the former is
>>>>
>>>> *
>>>> 296603151077074197308684124715622560525294501766069587161483751777320391554230009758029564174782423278870115094641644418265512090475911
>>>> *
>>>>
>>>> The problem is that the command ifactor(n) don't work, generate an
>>>> error, can help me??
>>>>
>>>> 1<#13267fb41fb33c74_13267b72b91849ef_132654fce756ae77_13264ae44588bf30_sdfootnote1anc>
>>>> http://www.immortaltheory.com/NumberTheory/RuthAaron.htm
>>>>
>>>>
>>>>
>>>> _______________________________________________
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>>>> Maxima at math.utexas.edu
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>>>>
>>>>
>>>
>>>
>>> --
>>> Blog: http://amca01.wordpress.com
>>> Web: http://bit.ly/Alasdair
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>>>
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>>>
>>>
>>
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>>
>>
>
>
> --
> Blog: http://amca01.wordpress.com
> Web: http://bit.ly/Alasdair
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>