limit / Continued fraction



You can set up the equations for a continued fraction quite easily:

 eqs: [  a = cfdisrep([0,3,2,1000,xx]),
           xx = cfdisrep([1,xx])   ]  /* the repeating part */ $

solve(eqs,[a,xx]);


On Sun, Oct 16, 2011 at 16:25, Adam Majewski <adammaj1 at o2.pl> wrote:

> Hi,
>
> I would like to find limit of Continued fraction [3,2,1000,1...]
> http://www.warwick.ac.uk/~masiay/Research/Siegel.html
>
> In maxima I can compute n-term finite fraction :
> a:
>
> [0,3,2,1000,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1]
>  (%o1)
>
> [0,3,2,1000,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1]
>  (%i2) t:cfdisrep(a)
>  (%o2) (1)/(3+(1)/(2+(1)/(1000+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1
> +(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1
> +(1)/(1+(1)/(1+(1)/(1+(1)/(1+ (1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1
> +(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1
> +(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1
> +(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1
> +(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1
> +(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+(1)/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1
> +1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/
> (1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1
> +1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/
> (1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1
> +1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1+1/(1
>
> +1/1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))
>  (%i3) float(t)
>
> Can I find it's limit ?
>
> TIA
>
> Adam
>
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