"Richard Hennessy" <rich.hennessy at verizon.net> writes:
> The indefinite integral of a continuous function which is finite
> valued on a region (a,b) is also continuous on the region (a,b).
> Check it out. The answer for this indefinite integral is wrong since
> it is discontinuous at zero. If I can figure out the right answer I
> will post it.
>
> Rich
Yes, but how does that relate to what Barton said? In general,
integration makes functions better behaved (more smooth). But the
problem here is that the integrand is nasty.
Rupert
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