Pau <vim.unix at googlemail.com> writes:
> Hi,
>
> I am sorry for a rather trivial question... If I have two equations like
>
> T(a,e) = a^4 ( 1 - e^3)
> H(a,e) = e^3 * constants * a^(-1)
>
> and I want to find the values of a ,e that equate them
>
> T(a,e) = H(a,e) ---> a = XXXX f(e)
Try
? solve
at the Maxima command line.
A couple notes:
-the assignment operator in Maxima is :
-the function definition operator is :=
-to solve your problem,
I did
(%i1) T : a^4*(1 - e^3) $ H : c*e^3/a $ display2d : false $
(%i4) solve(T=H,e);
(%o4) [e = (sqrt(3)*%i-1)*a^(5/3)/(2*(c+a^5)^(1/3)),
e = -(sqrt(3)*%i+1)*a^(5/3)/(2*(c+a^5)^(1/3)),
e = a^(5/3)/(c+a^5)^(1/3)]
>
> how could I do this in maxima? The best would be an example.
>
> Thanks for this nice piece of software. I am looking forward to
> learning how to use it in detail. Looks very promising.
>
> Cheers,
>
> Pau
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>
--
Leo Butler <l_butler at users.sourceforge.net>
SDF Public Access UNIX System - http://sdf.lonestar.org