part of equation as function
- Subject: part of equation as function
- From: Javier Arantegui
- Date: Wed, 14 Mar 2012 13:09:38 +0100
Hello!
On Wed, Mar 14, 2012 at 10:05 AM, Mike Valenzuela
<mickle.mouse at gmail.com> wrote:
> (%i1) f(x) := expand( x*(x+1) );
> (%o1) f(x) := expand(x (x + 1))
>
> (%i2) g(x) := ''( expand( x*(x+1) ) )
> (%o2) g(x) := x^2 + x
But:
(%i6) z=x+y;
(%o6) z=y+x
(%i8) f(x,y):=''rhs(%o6);
(%o8) f(x,y):=rhs(%o6)
(%i9) f(1,2);
(%o9) y+x
And:
(%i10) define(g(x,y),rhs(%o6));
(%o10) g(x,y):=y+x
(%i11) g(1,2);
(%o11) 3
Javier
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