On 3/27/2012 8:13 AM, Victor Hermans wrote:
> solve([7650*1.037^x=12250], [x]);
The proper syntax is simpler for a single equation:
solve(7650*1.037^x=12250, x);
This equation has an infinite number of solutions.
Radcan can be used to choose one interpretation of radicals and logs, and so
this seems to work: solve(radcan(log(...)), x)
It's possible that this task (finding approximate solutions of single
numerical equations) should be added to what solve does. However solve
is intended to find exact solutions, which this question does not
seem to require.
x=12.95885737160805...
in case it matters.