Solving an equation with integral



Rupert Swarbrick <rswarbrick at gmail.com> writes:
>   (%i2) factor(%);
>                                          40
>   (%o2)                       - ---------------------
>                                 (2 u + 5) (10 u - 33)
>
> Ah, great. Notice that your integrand has first-order poles at u = 3.3
> and u = 2.5 so we'd better assume that x is less than them. Integrating:

Oops: The pole is at -2.5. Fortunately, that doesn't affect the answer.

Rupert
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