Evaluating log(x)



Thanks guys,

I've updated my understanding accordingly.

On 21 August 2012 15:31, Stavros Macrakis <macrakis at alum.mit.edu> wrote:
> In Maxima terminology, the expression has already been "evaluated" (variable
> values substituted, functions called) and "simplified" (put into
> quasi-canonical form).  What you want to do is calculate its floating-point
> value:
>
> ex: 2*(1/2 - log(2)/2);
>
> float(ex) => .3068...
>
> or
>
> ex, numer => .3068...
>
>
> On Tue, Aug 21, 2012 at 10:25 AM, Andrew Martin <mr.a.martin at gmail.com>
> wrote:
>>
>> I have an expression including log().
>>
>> 2*(1/2 - log(2)/2);
>>
>> How can I make maxima evaluate the expression (hence returning approx
>> 0.307)?
>>
>> I've looked at the log simplification flags, simp and ev, but they
>> don't seem to have the effect I want.
>>
>> Cheers,
>>
>> Andrew
>>
>> --
>> Andrew Owen Martin
>> PhD Cand. at Goldsmiths, University of London (ma901am)
>> Investigating Enactivism with Sensory Substitution
>> M: 07901 65 35 28
>> http://aomartin.co.uk
>> _______________________________________________
>> Maxima mailing list
>> Maxima at math.utexas.edu
>> http://www.math.utexas.edu/mailman/listinfo/maxima
>
>



-- 
Andrew Owen Martin
PhD Cand. at Goldsmiths, University of London (ma901am)
Investigating Enactivism with Sensory Substitution
M: 07901 65 35 28
http://aomartin.co.uk