Silly me !!
Thank you. I was trying to solve
(%i1) eq: 4^x*(2^x-1)=4*(2^x+1);
(%o1) (2^x-1)*4^x=4*(2^x+1)
Now, with radcan, it works fine
(%i2) subst(x=log(y)/log(2),eq),radcan;
(%o2) y^3-y^2=4*y+4
De : macrakis at gmail.com [mailto:macrakis at gmail.com] De la part de Stavros
Macrakis
Envoy? : vendredi 7 septembre 2012 00:12
? : Jean-Claude Arbaut
Cc : maxima mailing list
Objet : Re: [Maxima] simplification of exponential
(%i1) 2^(log(x)/log(2));
(%o1) 2^(log(x)/log(2))
(%i2) radcan(%);
(%o2) x
On Thu, Sep 6, 2012 at 5:07 PM, Jean-Claude Arbaut
<jeanclaudearbaut at orange.fr> wrote:
2^(log(x)/log(2))