On Sun, 28 Oct 2012, Daniel Dalton wrote:
> 2. I've had a problem with simplification. The function f(x)=log(x) has
> been defined.
> Then I must set up the equation:
> 2*f(u)=f(2*v)+f(3*v)
> Then solve in terms of u:
> solve(2*f(u)=f(2*v)+f(3*v),u);
> [u = %e^(log(3*v)/2+log(2*v)/2)]
> I ratsimp (%) this, but it remains the same.
> Shouldn't it simplify down to sqrt(6)v?
Using radcan(%), instead of ratsimp(%), will give sqrt(2) sqrt(3) v.
> If so is there any way to avoid future problems like this, or are there
> just particular cases to be aware of?
>
> 3. I have two integrals, which must equal 3 and 2 respectively. So I
> assign the integrated equation to f(x) in maxima and attempt to solve
> for the two integrals like this simultaneously:
> f(x):=7*log(x);
>
> (%o3) f(x):=7*log(x)
> (%i4) solve([f(m*n)-f(1)=3, f(m/n)-f(1)=2],[m,n]);
> (%o4) []
>
> How do I find the solution to this? (I need an exact value)
I think you said you'd already loaded the to_poly_solve package, in
which case using the to_poly_solve function instead of the solve
function should do the trick here.
--
HTH,
Dan