solve's behaviour

• Subject: solve's behaviour
• From: Leo Butler
• Date: Fri, 02 Nov 2012 19:29:12 +0000

(%i1) solve(x^(1/3)=-1/2,x);

(%o1) [x^(1/3) = -1/2]

(%i2) solve(x^(1/3)=1/2,x);

(%o2) [x = 1/8]

I don't understand this behaviour, can someone explain?

-- 
Leo Butler                <l_butler at users.sourceforge.net>
SDF Public Access UNIX System -   http://sdf.lonestar.org

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