On Wed, Nov 21, 2012 at 4:14 PM, Edwin Woollett <woollett at charter.net>wrote:
> By the way, the "true value" of
> integrate (1/(1+sqrt(x)),x,0,1), used for %i3,
> was from the symbolic result produced by wolfram
> alpha; Maxima's integrate can't cope.
>
True, Maxima stupidly fails on integrate(1/(1+sqrt(x)),x,0,1),
but integrate(ratsimp(1/(1+sqrt(x))),x,0,1), algebraic:true does work....
-s