how to calculate "a" from this equation?



> p.s.: another question:
> If I write: ax+ay+az;
> how to get: a(x+y+z)????

ah, ok, I had to write this:
factor(a*x+a*y+a*z);
and I get this:
a*(z+y+x)

(why z+y+x and not x+y+z as I wrote?)