As Bill Wood says, in %i3, "10" means 2. For %i4, try ibase:1+1$
On Thu, Nov 22, 2012 at 12:01 PM, Antonio Lapira <antoniolapira at yahoo.it>wrote:
> I have problems swithing among bases
>
> for example:
> (%i1) ibase:16$
> (%i2) ibase:2$
> (%i3) ibase:10$
> (%i4) ibase:2$
>
> assignment: cannot assign 2 to ibase
> -- an error. To debug this try: debugmode(true);
>
> why?
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