(%i1) 1+(x+m)=(x+1)^2-x*(x+m); 2 (%o1) x + m + 1 = (x + 1) - x (x + m) (%i2) solve([%], [x]); m (%o2) [x = - -----] m - 1 (%i3) ok I solved that equation, but is it possible also display something that says: m != 1 ?