(%i1) 1+(x+m)=(x+1)^2-x*(x+m);
2
(%o1) x + m + 1 = (x + 1) - x (x + m)
(%i2) solve([%], [x]);
m
(%o2) [x = - -----]
m - 1
(%i3)
ok I solved that equation, but is it possible also display something that says: m != 1 ?