> I think you mean (C*z^6)/z \in (-\infty, 0)
Thx for the answer.
> You can get an idea on the intersection.
>
> load(draw) $
> ....
> I am not sure this is what you need.
Unfotunately my Maxima is old (5.22.1) and I do not have regions, so
code not works for me. I must update Maxima ( from long time )
You can see what I expect ( q - arm stars ) using my code from my
previous post in this thread.
The difference is only turn offset which I try to compute
http://commons.wikimedia.org/wiki/File:Parabolic_Julia_set_for_internal_angle_1_over_5_-_new_method.png
---
Adam
>
> --
> Mario
>
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