On Apr 16, 2013 1:59 AM, "Richard Hennessy" <rich.hennessy at verizon.net> wrote:
> Sorry if that confused anyone. I am not just trying to solve integrate(pwdelta(x-a)*f(x),x) but also integrate(diff_pwdelta(i,x-a) *f(x),x).
Ok but, to solve that, you can just use integration by parts, right? Since delta only picks up stuff at zero, you don't even have to worry about boundary values.
Rupert
Yes, integrate(du*v) = ?integrate(u*dv) because u*v = 0.
Rich