floating point ops; frexp & ldexp



>>>>> "Henry" == Henry Baker <hbaker1 at pipeline.com> writes:

    Henry> You're most likely correct, although even _forming_ the
    Henry> appropriate fp# to multiply by may be more expensive than
    Henry> simply doing ldexp; of course, this cost is amortized over
    Henry> the entire row/column.

Wouldn't computing 2^k be exactly one call to ldexp?  Or do you mean
figuring out what k to use?

Ray