a^n*b^n => (ab)^n



((-c+sqrt(c^2+4*d))/2/d)^n*((-c-sqrt(c^2+4*d))/2/d)^n;
This should simplify to (-1/d)^n, if I'm not mistaken, through application
of (a+b)(a-b)=a^2-b^2,
so we get (-4d/4d^2)^n as intermediate. How would I force maxima to do this
without actually having to input the subst command?


On Mon, Sep 9, 2013 at 12:02 PM, Stavros Macrakis <macrakis at alum.mit.edu>wrote:

> Does rootscontract (check doc for options) or radcan help?
>
> If you give us examples, we might be able to help more.
>
>       -s
> On Sep 9, 2013 3:16 AM, "Ralf Stephan" <gtrwst9 at gmail.com> wrote:
>
>> Thanks. The reason I'm asking is that I work with product expressions
>> having lots of square roots to the nth power, and they would simplify
>> nicely if only I could say: combine the bases, please. Explicitly
>> specifying substitutions for that would be tedious and error-prone.
>>
>>
>> ralf
>>
>> _______________________________________________
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>> Maxima at math.utexas.edu
>> http://www.math.utexas.edu/mailman/listinfo/maxima
>>
>>


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