The Maxima result is correct.
I tried to reproduce your result on Wolfram Alpha, and don't get the result
you got. Perhaps you made some small typo?
To put the Maxima result in the same form as the Wolfram Alpha result, use:
factor(diff((u*%e^v - 2*v*%e^(-u))^2,v))
-s
[image: Inline image 1]
On Sat, Nov 2, 2013 at 3:16 PM, Witold E Wolski <wewolski at gmail.com> wrote:
> The function I am trying to partially differentiate is:
> (u*exp(v) - 2*v*exp(-u))^2
>
> Struggling to find out what the correct result is:
>
>
> Maxima tells me it is:
> F(v,u)/dv = 2*( u*exp(v) - 2*exp(-u))*(u*exp(v) - 2*exp(-u)*v)
>
> http://www.wolframalpha.com
> F(v,u)/dv = 2*( u*exp(v) + 2*exp(-u))*(u*exp(v) + 2*exp(-u)*v)
>
>
>
> Not sure if either is correct?
>
>
>
>
>
> --
> Witold Eryk Wolski
> _______________________________________________
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> Maxima at math.utexas.edu
> http://www.math.utexas.edu/mailman/listinfo/maxima
>
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