Sorry, I did a mistake (typo). Wolfram and Maxima have the same results.
Thank you.
On 2 November 2013 21:25, Stavros Macrakis <macrakis at alum.mit.edu> wrote:
> The Maxima result is correct.
>
> I tried to reproduce your result on Wolfram Alpha, and don't get the
> result you got. Perhaps you made some small typo?
>
> To put the Maxima result in the same form as the Wolfram Alpha result, use:
>
> factor(diff((u*%e^v - 2*v*%e^(-u))^2,v))
>
> -s
>
>
> [image: Inline image 1]
>
>
> On Sat, Nov 2, 2013 at 3:16 PM, Witold E Wolski <wewolski at gmail.com>wrote:
>
>> The function I am trying to partially differentiate is:
>> (u*exp(v) - 2*v*exp(-u))^2
>>
>> Struggling to find out what the correct result is:
>>
>>
>> Maxima tells me it is:
>> F(v,u)/dv = 2*( u*exp(v) - 2*exp(-u))*(u*exp(v) - 2*exp(-u)*v)
>>
>> http://www.wolframalpha.com
>> F(v,u)/dv = 2*( u*exp(v) + 2*exp(-u))*(u*exp(v) + 2*exp(-u)*v)
>>
>>
>>
>> Not sure if either is correct?
>>
>>
>>
>>
>>
>> --
>> Witold Eryk Wolski
>> _______________________________________________
>> Maxima mailing list
>> Maxima at math.utexas.edu
>> http://www.math.utexas.edu/mailman/listinfo/maxima
>>
>
>
--
Witold Eryk Wolski
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