This might be a start--if you have something specific in mind, likely somebody will have an idea for you
(%i1) numerval(%z, (1+sqrt(7))/2);
(%o1) [%z]
(%i2) declare(%z, constant);
(%o2) done
Tell Maxima that %z^2 = (2*%z+3)/2)
(%i3) let(%z^2, (2*%z+3)/2);
(%o3) %z^2 --> (2*%z+3)/2
Simplify powers of %z
(%i4) letsimp([%z^2,%z^3,%z^4]);
(%o4) [%z+3/2,(5*%z)/2+3/2,4*%z+15/4]
I think maybe numerval assumes a floating point value--oops
(%i6) float(%z);
(%o6) (sqrt(7)+1)/2
(%i7) float(%);
(%o7) 1.822875655532295
So %1 should be numerval(%z, 1.822875655532295). But you might check the user documentation for numerval.
--Barton
________________________________
From: maxima-bounces at math.utexas.edu <maxima-bounces at math.utexas.edu> on behalf of Ricardo JF <rcrdjf at hotmail.com>
Sent: Saturday, December 7, 2013 08:09
To: maxima at math.utexas.edu
Subject: constant (basic)
i know that %pi,%phi,%e are constants, but
how can i create a particular one:
example:
r --> (1+sqrt(7))/2=1,82287565553
%r,numer; -->1,82287565
thanks.