Jurgis,
>From my experiences writing similar "algebraic expand" code in Maxima
http://matsrv3.bham.ac.uk/dev/expand.php
you are going to have to get involved in expressions and they way they are
represented. I think you will be repaid for the time taken to do this.....
Chris
On Mon, 27 Nov 2006, Jurgis Pralgauskis wrote:
> and maybe Maxima can show the inputed infix expression in the form of
> http://en.wikipedia.org/wiki/Polish_notation ?
> as I understand LISP thinks the prefix-way.. but the ?print result
> looks too spagetti-like to me..
>
> Thanks again.
>
>
> Stavros Macrakis wrote:
>> On 11/26/06, Jurgis Pralgauskis <jurgpral at soften.ktu.lt> wrote:
>>> could smb point me how to access the formula parse tree.
>>
>> The internal form of Maxima expressions is a Lisp s-expression, which
>> you can see using the ?print function. For example,
>>
>> sin(x)/x-x-1
>>
>> is represented as
>>
>> ((MPLUS SIMP) -1
>> ((MTIMES SIMP) -1 $X)
>> ((MTIMES SIMP) ((MEXPT SIMP) $X -1)
>> ((%SIN SIMP) $X)))
>>
>> There are a few salient points here:
>>
>> -- op(a) is represented as ((OP ...) a) The ... are various flags,
>> most commonly SIMP indicating that the expression has already been
>> simplified.
>> -- x/y is represented as x*y^-1
>> -- -x is represented as -1*x
>> -- there is a canonical ordering of terms in simplified expressions
>>
>> You can also access the operator and operands using the OP and ARGS
>> functions in Maxima itself. These normally reflect the *external*
>> form of the expression, so op(-x)=> - (not *). To see the internal
>> forms, set inflag:true.
>>
>> -s
>>
>
>
> --
> Jurgis Pralgauskis
> mob.: +37061677613; skype: dz0rdzas; (ICQ# 147307045 (retai tikrinu))
> Don't worry, be happy :) and make things better ;)
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