Richard Fateman <fateman <at> cs.berkeley.edu> writes:
> sin(sin(sin(sin(sin(sin(taylor (sin(x^3)^5,x,0,20)))))) gives the same
> result in 0.00 seconds.
This is a very interesting result. It suggests that perhaps the problems with
limit and taylor can be solved this way. (with taylor inside!).
If this is the case my idea (a very simple implementation of equivalency of
infinitesimal, Calculus I stuff) is not going to make limit better.
Anyway, a wish to thank you and Barton for commenting this ideas and testing this
simple code.
Best regards.
- M